4401041343331 has 2 divisors, whose sum is σ = 4401041343332. Its totient is φ = 4401041343330.

The previous prime is 4401041343253. The next prime is 4401041343341. The reversal of 4401041343331 is 1333431401044.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4401041343331 - 2¹⁷ = 4401041212259 is a prime.

It is a super-2 number, since 2×4401041343331² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4401041343293 and 4401041343302.

It is not a weakly prime, because it can be changed into another prime (4401041343341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2200520671665 + 2200520671666.

It is an arithmetic number, because the mean of its divisors is an integer number (2200520671666).

Almost surely, 2^{4401041343331} is an apocalyptic number.

4401041343331 is a deficient number, since it is larger than the sum of its proper divisors (1).

4401041343331 is an equidigital number, since it uses as much as digits as its factorization.

4401041343331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 4401041343331 its reverse (1333431401044), we get a palindrome (5734472744375).

The spelling of 4401041343331 in words is "four trillion, four hundred one billion, forty-one million, three hundred forty-three thousand, three hundred thirty-one".