Search a number
-
+
44013000021 = 314671000007
BaseRepresentation
bin101000111111011000…
…010001010101010101
311012121100020001121220
4220333120101111111
51210114312000041
632115211200553
73115453220214
oct507730212525
9135540201556
1044013000021
1117736211391
128643a46159
1341c55a61a3
1421b754707b
151228e78d66
hexa3f611555

44013000021 has 4 divisors (see below), whose sum is σ = 58684000032. Its totient is φ = 29342000012.

The previous prime is 44013000013. The next prime is 44013000037. The reversal of 44013000021 is 12000031044.

44013000021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 44013000021 - 23 = 44013000013 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (44013000011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7335500001 + ... + 7335500006.

It is an arithmetic number, because the mean of its divisors is an integer number (14671000008).

Almost surely, 244013000021 is an apocalyptic number.

It is an amenable number.

44013000021 is a deficient number, since it is larger than the sum of its proper divisors (14671000011).

44013000021 is a wasteful number, since it uses less digits than its factorization.

44013000021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14671000010.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 44013000021 its reverse (12000031044), we get a palindrome (56013031065).

The spelling of 44013000021 in words is "forty-four billion, thirteen million, twenty-one", and thus it is an aban number.

Divisors: 1 3 14671000007 44013000021