44013001141 has 2 divisors, whose sum is σ = 44013001142. Its totient is φ = 44013001140.

The previous prime is 44013001091. The next prime is 44013001157. The reversal of 44013001141 is 14110031044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40624014916 + 3388986225 = 201554^2 + 58215^2 .

It is a cyclic number.

It is not a de Polignac number, because 44013001141 - 2⁷ = 44013001013 is a prime.

It is a super-3 number, since 3×44013001141³ (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44013041141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22006500570 + 22006500571.

It is an arithmetic number, because the mean of its divisors is an integer number (22006500571).

Almost surely, 2^44013001141 is an apocalyptic number.

It is an amenable number.

44013001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

44013001141 is an equidigital number, since it uses as much as digits as its factorization.

44013001141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 44013001141 its reverse (14110031044), we get a palindrome (58123032185).

The spelling of 44013001141 in words is "forty-four billion, thirteen million, one thousand, one hundred forty-one".