Base | Representation |
---|---|
bin | 1100110011110101001… |
… | …01111110100001111001 |
3 | 1120002002100112102011122 |
4 | 12121322211332201321 |
5 | 24202403210034433 |
6 | 534111001235025 |
7 | 43541110340135 |
oct | 6317245764171 |
9 | 1502070472148 |
10 | 440143439993 |
11 | 15a733551a94 |
12 | 71377192a75 |
13 | 3267533392a |
14 | 1743582c3c5 |
15 | b6b0cb6198 |
hex | 667a97e879 |
440143439993 has 2 divisors, whose sum is σ = 440143439994. Its totient is φ = 440143439992.
The previous prime is 440143439947. The next prime is 440143440041. The reversal of 440143439993 is 399934341044.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 439637954704 + 505485289 = 663052^2 + 22483^2 .
It is a cyclic number.
It is not a de Polignac number, because 440143439993 - 26 = 440143439929 is a prime.
It is not a weakly prime, because it can be changed into another prime (440143435993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220071719996 + 220071719997.
It is an arithmetic number, because the mean of its divisors is an integer number (220071719997).
Almost surely, 2440143439993 is an apocalyptic number.
It is an amenable number.
440143439993 is a deficient number, since it is larger than the sum of its proper divisors (1).
440143439993 is an equidigital number, since it uses as much as digits as its factorization.
440143439993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5038848, while the sum is 53.
The spelling of 440143439993 in words is "four hundred forty billion, one hundred forty-three million, four hundred thirty-nine thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •