Base | Representation |
---|---|
bin | 1100110011111101011… |
… | …00000001100011010111 |
3 | 1120002021010210102202221 |
4 | 12121332230001203113 |
5 | 24203023301242403 |
6 | 534121453443211 |
7 | 43542603254410 |
oct | 6317654014327 |
9 | 1502233712687 |
10 | 440212134103 |
11 | 15a769300985 |
12 | 713961a0507 |
13 | 32686635c31 |
14 | 174409d0807 |
15 | b6b6d34dbd |
hex | 667eb018d7 |
440212134103 has 4 divisors (see below), whose sum is σ = 503099581840. Its totient is φ = 377324686368.
The previous prime is 440212134067. The next prime is 440212134121. The reversal of 440212134103 is 301431212044.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 440212134103 - 213 = 440212125911 is a prime.
It is a super-2 number, since 2×4402121341032 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (440212134503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31443723858 + ... + 31443723871.
It is an arithmetic number, because the mean of its divisors is an integer number (125774895460).
Almost surely, 2440212134103 is an apocalyptic number.
440212134103 is a deficient number, since it is larger than the sum of its proper divisors (62887447737).
440212134103 is an equidigital number, since it uses as much as digits as its factorization.
440212134103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62887447736.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 440212134103 its reverse (301431212044), we get a palindrome (741643346147).
The spelling of 440212134103 in words is "four hundred forty billion, two hundred twelve million, one hundred thirty-four thousand, one hundred three".
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