Base | Representation |
---|---|
bin | 101000111111111000… |
… | …010100011011100001 |
3 | 11012121221000220000212 |
4 | 220333320110123201 |
5 | 1210123434320223 |
6 | 32120111223505 |
7 | 3115614510611 |
oct | 507770243341 |
9 | 135557026025 |
10 | 44021401313 |
11 | 1773aa2a3aa |
12 | 8646817b95 |
13 | 41c7258176 |
14 | 21b86d2a41 |
15 | 1229a88278 |
hex | a3fe146e1 |
44021401313 has 2 divisors, whose sum is σ = 44021401314. Its totient is φ = 44021401312.
The previous prime is 44021401297. The next prime is 44021401357. The reversal of 44021401313 is 31310412044.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31220062864 + 12801338449 = 176692^2 + 113143^2 .
It is a cyclic number.
It is not a de Polignac number, because 44021401313 - 24 = 44021401297 is a prime.
It is not a weakly prime, because it can be changed into another prime (44021401013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22010700656 + 22010700657.
It is an arithmetic number, because the mean of its divisors is an integer number (22010700657).
Almost surely, 244021401313 is an apocalyptic number.
It is an amenable number.
44021401313 is a deficient number, since it is larger than the sum of its proper divisors (1).
44021401313 is an equidigital number, since it uses as much as digits as its factorization.
44021401313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 44021401313 its reverse (31310412044), we get a palindrome (75331813357).
The spelling of 44021401313 in words is "forty-four billion, twenty-one million, four hundred one thousand, three hundred thirteen".
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