44024141113 has 4 divisors (see below), whose sum is σ = 44024717968. Its totient is φ = 44023564260.

The previous prime is 44024141101. The next prime is 44024141123. The reversal of 44024141113 is 31114142044.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 44024141113 - 2²⁵ = 43990586681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (44024141123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152643 + ... + 333688.

It is an arithmetic number, because the mean of its divisors is an integer number (11006179492).

Almost surely, 2^44024141113 is an apocalyptic number.

It is an amenable number.

44024141113 is a deficient number, since it is larger than the sum of its proper divisors (576855).

44024141113 is an equidigital number, since it uses as much as digits as its factorization.

44024141113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 576854.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 44024141113 its reverse (31114142044), we get a palindrome (75138283157).

The spelling of 44024141113 in words is "forty-four billion, twenty-four million, one hundred forty-one thousand, one hundred thirteen".