44040000013 has 2 divisors, whose sum is σ = 44040000014. Its totient is φ = 44040000012.

The previous prime is 44039999959. The next prime is 44040000047. The reversal of 44040000013 is 31000004044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39983201764 + 4056798249 = 199958^2 + 63693^2 .

It is a cyclic number.

It is not a de Polignac number, because 44040000013 - 2²¹ = 44037902861 is a prime.

It is a super-2 number, since 2×44040000013² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44040000073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22020000006 + 22020000007.

It is an arithmetic number, because the mean of its divisors is an integer number (22020000007).

Almost surely, 2^44040000013 is an apocalyptic number.

It is an amenable number.

44040000013 is a deficient number, since it is larger than the sum of its proper divisors (1).

44040000013 is an equidigital number, since it uses as much as digits as its factorization.

44040000013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 16.

Adding to 44040000013 its reverse (31000004044), we get a palindrome (75040004057).

The spelling of 44040000013 in words is "forty-four billion, forty million, thirteen", and thus it is an aban number.