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440401330121 is a prime number
BaseRepresentation
bin1100110100010011111…
…01101111111111001001
31120002202022210120220212
412122021331233333021
524203420220030441
6534152332530505
743550361353324
oct6321175577711
91502668716825
10440401330121
1115a856084725
1271429620a35
13326b68a973c
141745bb9d7bb
15b6c8757eeb
hex6689f6ffc9

440401330121 has 2 divisors, whose sum is σ = 440401330122. Its totient is φ = 440401330120.

The previous prime is 440401330097. The next prime is 440401330129. The reversal of 440401330121 is 121033104044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 440258790400 + 142539721 = 663520^2 + 11939^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-440401330121 is a prime.

It is not a weakly prime, because it can be changed into another prime (440401330129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220200665060 + 220200665061.

It is an arithmetic number, because the mean of its divisors is an integer number (220200665061).

Almost surely, 2440401330121 is an apocalyptic number.

It is an amenable number.

440401330121 is a deficient number, since it is larger than the sum of its proper divisors (1).

440401330121 is an equidigital number, since it uses as much as digits as its factorization.

440401330121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 440401330121 its reverse (121033104044), we get a palindrome (561434434165).

The spelling of 440401330121 in words is "four hundred forty billion, four hundred one million, three hundred thirty thousand, one hundred twenty-one".