Base | Representation |
---|---|
bin | 10100000001101111001101… |
… | …00011011000011001101101 |
3 | 12202221012101000021100002121 |
4 | 22000313212203120121231 |
5 | 21233023230414024212 |
6 | 233355435043552541 |
7 | 12163540261043641 |
oct | 1200674643303155 |
9 | 182835330240077 |
10 | 44040167720557 |
11 | 1303a36a60a708 |
12 | 4b3334308b751 |
13 | 1b75c7c10a388 |
14 | ac37ac3a4c21 |
15 | 5158bc28dd07 |
hex | 280de68d866d |
44040167720557 has 4 divisors (see below), whose sum is σ = 44040180993120. Its totient is φ = 44040154447996.
The previous prime is 44040167720543. The next prime is 44040167720573. The reversal of 44040167720557 is 75502776104044.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 44040167720557 - 231 = 44038020236909 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44040167720597) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3306738 + ... + 9950620.
It is an arithmetic number, because the mean of its divisors is an integer number (11010045248280).
Almost surely, 244040167720557 is an apocalyptic number.
It is an amenable number.
44040167720557 is a deficient number, since it is larger than the sum of its proper divisors (13272563).
44040167720557 is an equidigital number, since it uses as much as digits as its factorization.
44040167720557 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13272562.
The product of its (nonzero) digits is 6585600, while the sum is 52.
The spelling of 44040167720557 in words is "forty-four trillion, forty billion, one hundred sixty-seven million, seven hundred twenty thousand, five hundred fifty-seven".
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