440403012131 has 4 divisors (see below), whose sum is σ = 443870752512. Its totient is φ = 436935271752.

The previous prime is 440403012103. The next prime is 440403012151. The reversal of 440403012131 is 131210304044.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 440403012131 - 2¹⁸ = 440402749987 is a prime.

It is a super-2 number, since 2×440403012131² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 440403012097 and 440403012106.

It is not an unprimeable number, because it can be changed into a prime (440403012151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1733870000 + ... + 1733870253.

It is an arithmetic number, because the mean of its divisors is an integer number (110967688128).

Almost surely, 2^440403012131 is an apocalyptic number.

440403012131 is a deficient number, since it is larger than the sum of its proper divisors (3467740381).

440403012131 is a wasteful number, since it uses less digits than its factorization.

440403012131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3467740380.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 440403012131 its reverse (131210304044), we get a palindrome (571613316175).

The spelling of 440403012131 in words is "four hundred forty billion, four hundred three million, twelve thousand, one hundred thirty-one".