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4405203431311 = 10940414710379
BaseRepresentation
bin100000000011010101010…
…0101011110111110001111
3120121010121012102202210011
41000012222211132332033
51034133324034300221
613211420021454051
7633160022226604
oct100065245367617
916533535382704
104405203431311
111449266547a21
125b1911871327
1325c5414816c7
141132da5da6ab
15798c95e11e1
hex401aa95ef8f

4405203431311 has 4 divisors (see below), whose sum is σ = 4445618141800. Its totient is φ = 4364788720824.

The previous prime is 4405203431219. The next prime is 4405203431323. The reversal of 4405203431311 is 1131343025044.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4405203431311 - 237 = 4267764477839 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4405203431351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20207355081 + ... + 20207355298.

It is an arithmetic number, because the mean of its divisors is an integer number (1111404535450).

Almost surely, 24405203431311 is an apocalyptic number.

4405203431311 is a deficient number, since it is larger than the sum of its proper divisors (40414710489).

4405203431311 is a wasteful number, since it uses less digits than its factorization.

4405203431311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40414710488.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 4405203431311 its reverse (1131343025044), we get a palindrome (5536546456355).

The spelling of 4405203431311 in words is "four trillion, four hundred five billion, two hundred three million, four hundred thirty-one thousand, three hundred eleven".

Divisors: 1 109 40414710379 4405203431311