4412025140011 has 4 divisors (see below), whose sum is σ = 4531269062752. Its totient is φ = 4292781217272.

The previous prime is 4412025140009. The next prime is 4412025140041. The reversal of 4412025140011 is 1100415202144.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4412025140011 - 2¹ = 4412025140009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4412025140041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59621961315 + ... + 59621961388.

It is an arithmetic number, because the mean of its divisors is an integer number (1132817265688).

Almost surely, 2^{4412025140011} is an apocalyptic number.

4412025140011 is a deficient number, since it is larger than the sum of its proper divisors (119243922741).

4412025140011 is a wasteful number, since it uses less digits than its factorization.

4412025140011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119243922740.

The product of its (nonzero) digits is 1280, while the sum is 25.

The spelling of 4412025140011 in words is "four trillion, four hundred twelve billion, twenty-five million, one hundred forty thousand, eleven".