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4412234113471 is a prime number
BaseRepresentation
bin100000000110100110110…
…1001011010000110111111
3120121210202011220102120201
41000031031221122012333
51034242223413112341
613214541413424331
7633526163105332
oct100151551320677
916553664812521
104412234113471
111451244148548
125b315433b0a7
132600c1c3ac72
141137a6262619
1579b8b96b331
hex4034da5a1bf

4412234113471 has 2 divisors, whose sum is σ = 4412234113472. Its totient is φ = 4412234113470.

The previous prime is 4412234113369. The next prime is 4412234113513. The reversal of 4412234113471 is 1743114322144.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4412234113471 is a prime.

It is a super-3 number, since 3×44122341134713 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4412234113471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4412234113171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2206117056735 + 2206117056736.

It is an arithmetic number, because the mean of its divisors is an integer number (2206117056736).

Almost surely, 24412234113471 is an apocalyptic number.

4412234113471 is a deficient number, since it is larger than the sum of its proper divisors (1).

4412234113471 is an equidigital number, since it uses as much as digits as its factorization.

4412234113471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 64512, while the sum is 37.

The spelling of 4412234113471 in words is "four trillion, four hundred twelve billion, two hundred thirty-four million, one hundred thirteen thousand, four hundred seventy-one".