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441224432190041 is a prime number
BaseRepresentation
bin110010001010010101001000…
…1100011000000001001011001
32010212020122101022101002102012
41210110222101203000021121
5430313010114120040131
64202223412250315305
7161636261514624023
oct14424522143001131
92125218338332365
10441224432190041
1111865125a301855
12415a0301728b35
1315c273930cb8a6
147ad553b02b013
1536023d794852b
hex1914a918c0259

441224432190041 has 2 divisors, whose sum is σ = 441224432190042. Its totient is φ = 441224432190040.

The previous prime is 441224432190019. The next prime is 441224432190043. The reversal of 441224432190041 is 140091234422144.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 420259389052441 + 20965043137600 = 20500229^2 + 4578760^2 .

It is a cyclic number.

It is not a de Polignac number, because 441224432190041 - 218 = 441224431927897 is a prime.

It is a super-2 number, since 2×4412244321900412 (a number of 30 digits) contains 22 as substring.

Together with 441224432190043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (441224432190043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220612216095020 + 220612216095021.

It is an arithmetic number, because the mean of its divisors is an integer number (220612216095021).

Almost surely, 2441224432190041 is an apocalyptic number.

It is an amenable number.

441224432190041 is a deficient number, since it is larger than the sum of its proper divisors (1).

441224432190041 is an equidigital number, since it uses as much as digits as its factorization.

441224432190041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 221184, while the sum is 41.

The spelling of 441224432190041 in words is "four hundred forty-one trillion, two hundred twenty-four billion, four hundred thirty-two million, one hundred ninety thousand, forty-one".