441426256554131 has 2 divisors, whose sum is σ = 441426256554132. Its totient is φ = 441426256554130.

The previous prime is 441426256554121. The next prime is 441426256554133. The reversal of 441426256554131 is 131455652624144.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-441426256554131 is a prime.

It is a super-2 number, since 2×441426256554131² (a number of 30 digits) contains 22 as substring.

Together with 441426256554133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (441426256554133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220713128277065 + 220713128277066.

It is an arithmetic number, because the mean of its divisors is an integer number (220713128277066).

Almost surely, 2^{441426256554131} is an apocalyptic number.

441426256554131 is a deficient number, since it is larger than the sum of its proper divisors (1).

441426256554131 is an equidigital number, since it uses as much as digits as its factorization.

441426256554131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13824000, while the sum is 53.

The spelling of 441426256554131 in words is "four hundred forty-one trillion, four hundred twenty-six billion, two hundred fifty-six million, five hundred fifty-four thousand, one hundred thirty-one".