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44143588534141 is a prime number
BaseRepresentation
bin10100000100101111110101…
…11010011110011101111101
312210022002022120210000101201
422002113322322132131331
521241222032131043031
6233515141250535501
712204161163334615
oct1202277272363575
9183262276700351
1044143588534141
111307a2109a7678
124b4b3a6597591
131b8295154c465
14ac87bd88da45
15518421992d61
hex2825fae9e77d

44143588534141 has 2 divisors, whose sum is σ = 44143588534142. Its totient is φ = 44143588534140.

The previous prime is 44143588534099. The next prime is 44143588534151. The reversal of 44143588534141 is 14143588534144.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23012926358041 + 21130662176100 = 4797179^2 + 4596810^2 .

It is a cyclic number.

It is not a de Polignac number, because 44143588534141 - 227 = 44143454316413 is a prime.

It is a super-2 number, since 2×441435885341412 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44143588534151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22071794267070 + 22071794267071.

It is an arithmetic number, because the mean of its divisors is an integer number (22071794267071).

Almost surely, 244143588534141 is an apocalyptic number.

It is an amenable number.

44143588534141 is a deficient number, since it is larger than the sum of its proper divisors (1).

44143588534141 is an equidigital number, since it uses as much as digits as its factorization.

44143588534141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14745600, while the sum is 55.

The spelling of 44143588534141 in words is "forty-four trillion, one hundred forty-three billion, five hundred eighty-eight million, five hundred thirty-four thousand, one hundred forty-one".