Base | Representation |
---|---|
bin | 10100000100110010100010… |
… | …00001011110110011101001 |
3 | 12210022020001021012012122020 |
4 | 22002121101001132303221 |
5 | 21241233012000223423 |
6 | 233515540455215053 |
7 | 12204242035025052 |
oct | 1202312101366351 |
9 | 183266037165566 |
10 | 44145033211113 |
11 | 1307a89243088a |
12 | 4b4b72a377489 |
13 | 1b82b219414c3 |
14 | ac88b96b1729 |
15 | 5184a87104e3 |
hex | 28265105ece9 |
44145033211113 has 4 divisors (see below), whose sum is σ = 58860044281488. Its totient is φ = 29430022140740.
The previous prime is 44145033211087. The next prime is 44145033211129. The reversal of 44145033211113 is 31111233054144.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 44145033211113 - 217 = 44145033080041 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (44145033211133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7357505535183 + ... + 7357505535188.
It is an arithmetic number, because the mean of its divisors is an integer number (14715011070372).
Almost surely, 244145033211113 is an apocalyptic number.
It is an amenable number.
44145033211113 is a deficient number, since it is larger than the sum of its proper divisors (14715011070375).
44145033211113 is a wasteful number, since it uses less digits than its factorization.
44145033211113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14715011070374.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 44145033211113 its reverse (31111233054144), we get a palindrome (75256266265257).
The spelling of 44145033211113 in words is "forty-four trillion, one hundred forty-five billion, thirty-three million, two hundred eleven thousand, one hundred thirteen".
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