Search a number
-
+
442103031410501 is a prime number
BaseRepresentation
bin110010010000101110010001…
…0001001000010111101000101
32010222100122012101210221010002
41210201130202021002331011
5430421404002020114001
64204135155005011045
7162056614154030216
oct14441344211027505
92128318171727102
10442103031410501
1111895a92a6a118a
1241702642853a85
1315c8c1a1c1a826
147b25c8809540d
15361a1ab25d46b
hex1921722242f45

442103031410501 has 2 divisors, whose sum is σ = 442103031410502. Its totient is φ = 442103031410500.

The previous prime is 442103031410497. The next prime is 442103031410563. The reversal of 442103031410501 is 105014130301244.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 376157685196225 + 65945346214276 = 19394785^2 + 8120674^2 .

It is a cyclic number.

It is not a de Polignac number, because 442103031410501 - 22 = 442103031410497 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (442103031419501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221051515705250 + 221051515705251.

It is an arithmetic number, because the mean of its divisors is an integer number (221051515705251).

Almost surely, 2442103031410501 is an apocalyptic number.

It is an amenable number.

442103031410501 is a deficient number, since it is larger than the sum of its proper divisors (1).

442103031410501 is an equidigital number, since it uses as much as digits as its factorization.

442103031410501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 442103031410501 its reverse (105014130301244), we get a palindrome (547117161711745).

The spelling of 442103031410501 in words is "four hundred forty-two trillion, one hundred three billion, thirty-one million, four hundred ten thousand, five hundred one".