Base | Representation |
---|---|
bin | 110010010000110011000001… |
… | …0110000111011001111111111 |
3 | 2010222101121120000121112220221 |
4 | 1210201212002300323033333 |
5 | 430422040410024141111 |
6 | 4204144004130122211 |
7 | 162060425203100041 |
oct | 14441460260731777 |
9 | 2128347500545827 |
10 | 442113242412031 |
11 | 11896419a522823 |
12 | 41704612420367 |
13 | 15c9013b544978 |
14 | 7b26576261a91 |
15 | 361a5a78ea371 |
hex | 1921982c3b3ff |
442113242412031 has 2 divisors, whose sum is σ = 442113242412032. Its totient is φ = 442113242412030.
The previous prime is 442113242412019. The next prime is 442113242412073. The reversal of 442113242412031 is 130214242311244.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 442113242412031 - 25 = 442113242411999 is a prime.
It is a super-2 number, since 2×4421132424120312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (442143242412031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221056621206015 + 221056621206016.
It is an arithmetic number, because the mean of its divisors is an integer number (221056621206016).
Almost surely, 2442113242412031 is an apocalyptic number.
442113242412031 is a deficient number, since it is larger than the sum of its proper divisors (1).
442113242412031 is an equidigital number, since it uses as much as digits as its factorization.
442113242412031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 442113242412031 its reverse (130214242311244), we get a palindrome (572327484723275).
The spelling of 442113242412031 in words is "four hundred forty-two trillion, one hundred thirteen billion, two hundred forty-two million, four hundred twelve thousand, thirty-one".
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