Base | Representation |
---|---|
bin | 110010010000110011000001… |
… | …0110000111011010001010111 |
3 | 2010222101121120000121120001012 |
4 | 1210201212002300323101113 |
5 | 430422040410024141434 |
6 | 4204144004130122435 |
7 | 162060425203100225 |
oct | 14441460260732127 |
9 | 2128347500546035 |
10 | 442113242412119 |
11 | 11896419a5228a3 |
12 | 4170461242041b |
13 | 15c9013b544a15 |
14 | 7b26576261b15 |
15 | 361a5a78ea3ce |
hex | 1921982c3b457 |
442113242412119 has 2 divisors, whose sum is σ = 442113242412120. Its totient is φ = 442113242412118.
The previous prime is 442113242412073. The next prime is 442113242412133. The reversal of 442113242412119 is 911214242311244.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 442113242412119 - 216 = 442113242346583 is a prime.
It is a super-2 number, since 2×4421132424121192 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (442113242412169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221056621206059 + 221056621206060.
It is an arithmetic number, because the mean of its divisors is an integer number (221056621206060).
Almost surely, 2442113242412119 is an apocalyptic number.
442113242412119 is a deficient number, since it is larger than the sum of its proper divisors (1).
442113242412119 is an equidigital number, since it uses as much as digits as its factorization.
442113242412119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 110592, while the sum is 41.
The spelling of 442113242412119 in words is "four hundred forty-two trillion, one hundred thirteen billion, two hundred forty-two million, four hundred twelve thousand, one hundred nineteen".
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