Base | Representation |
---|---|
bin | 10100000110101111100011… |
… | …00111011111111010101101 |
3 | 12210112122021220010001022120 |
4 | 22003113301213133322231 |
5 | 21243332441410304013 |
6 | 234010440544503153 |
7 | 12212136225461166 |
oct | 1203276147377255 |
9 | 183478256101276 |
10 | 44212152041133 |
11 | 130a62a524523a |
12 | 4b6074031aab9 |
13 | 1b8925a1abb3b |
14 | acbc457b476d |
15 | 51a0d5e01123 |
hex | 2835f19dfead |
44212152041133 has 16 divisors (see below), whose sum is σ = 62418091651776. Its totient is φ = 27740542219520.
The previous prime is 44212152041131. The next prime is 44212152041149. The reversal of 44212152041133 is 33114025121244.
It is a cyclic number.
It is not a de Polignac number, because 44212152041133 - 21 = 44212152041131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 44212152041094 and 44212152041103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44212152041131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3046098 + ... + 9884483.
It is an arithmetic number, because the mean of its divisors is an integer number (3901130728236).
Almost surely, 244212152041133 is an apocalyptic number.
It is an amenable number.
44212152041133 is a deficient number, since it is larger than the sum of its proper divisors (18205939610643).
44212152041133 is a wasteful number, since it uses less digits than its factorization.
44212152041133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12997644.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 44212152041133 its reverse (33114025121244), we get a palindrome (77326177162377).
The spelling of 44212152041133 in words is "forty-four trillion, two hundred twelve billion, one hundred fifty-two million, forty-one thousand, one hundred thirty-three".
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