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4422142313151 = 31474047437717
BaseRepresentation
bin100000001011001110000…
…1110001100001010111111
3120122202022200221010100020
41000112130032030022333
51034423021413010101
613223300520503223
7634326544316013
oct100263416141277
916582280833306
104422142313151
111455469061622
125b505a61ab13
132610108c5c04
1411406612a543
157a06b744136
hex4059c38c2bf

4422142313151 has 4 divisors (see below), whose sum is σ = 5896189750872. Its totient is φ = 2948094875432.

The previous prime is 4422142313129. The next prime is 4422142313249. The reversal of 4422142313151 is 1513132412244.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4422142313151 - 213 = 4422142304959 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4422142313851) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 737023718856 + ... + 737023718861.

It is an arithmetic number, because the mean of its divisors is an integer number (1474047437718).

Almost surely, 24422142313151 is an apocalyptic number.

4422142313151 is a deficient number, since it is larger than the sum of its proper divisors (1474047437721).

4422142313151 is a wasteful number, since it uses less digits than its factorization.

4422142313151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1474047437720.

The product of its digits is 23040, while the sum is 33.

Adding to 4422142313151 its reverse (1513132412244), we get a palindrome (5935274725395).

The spelling of 4422142313151 in words is "four trillion, four hundred twenty-two billion, one hundred forty-two million, three hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 3 1474047437717 4422142313151