Base | Representation |
---|---|
bin | 100000001100001001011… |
… | …1011111011010111011111 |
3 | 120122221110111200000212022 |
4 | 1000120102323323113133 |
5 | 1034441111301430211 |
6 | 13224230305530355 |
7 | 634430110435205 |
oct | 100302273732737 |
9 | 16587414600768 |
10 | 4424134014431 |
11 | 14562a035023a |
12 | 5b55156439bb |
13 | 26126a425b91 |
14 | 1141b4865075 |
15 | 7a136517bdb |
hex | 40612efb5df |
4424134014431 has 2 divisors, whose sum is σ = 4424134014432. Its totient is φ = 4424134014430.
The previous prime is 4424134014409. The next prime is 4424134014473. The reversal of 4424134014431 is 1344104314244.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4424134014431 - 218 = 4424133752287 is a prime.
It is a super-2 number, since 2×44241340144312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4424134014391 and 4424134014400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4424134014031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2212067007215 + 2212067007216.
It is an arithmetic number, because the mean of its divisors is an integer number (2212067007216).
Almost surely, 24424134014431 is an apocalyptic number.
4424134014431 is a deficient number, since it is larger than the sum of its proper divisors (1).
4424134014431 is an equidigital number, since it uses as much as digits as its factorization.
4424134014431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 4424134014431 its reverse (1344104314244), we get a palindrome (5768238328675).
The spelling of 4424134014431 in words is "four trillion, four hundred twenty-four billion, one hundred thirty-four million, fourteen thousand, four hundred thirty-one".
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