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4430220043201 = 9614274607963
BaseRepresentation
bin100000001110111110110…
…1100010010001111000001
3120200112011122121022211021
41000131331230102033001
51040041042312340301
613231114234345441
7635033661016261
oct100357554221701
916615148538737
104430220043201
11145893379a787
125b673388b281
132619ca283134
141145d0c697a1
157a3909958a1
hex4077db123c1

4430220043201 has 4 divisors (see below), whose sum is σ = 4430225612592. Its totient is φ = 4430214473812.

The previous prime is 4430220043177. The next prime is 4430220043267. The reversal of 4430220043201 is 1023400220344.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4430220043201 - 25 = 4430220043169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4430220049201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1342555 + ... + 3265408.

It is an arithmetic number, because the mean of its divisors is an integer number (1107556403148).

Almost surely, 24430220043201 is an apocalyptic number.

It is an amenable number.

4430220043201 is a deficient number, since it is larger than the sum of its proper divisors (5569391).

4430220043201 is an equidigital number, since it uses as much as digits as its factorization.

4430220043201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5569390.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 4430220043201 its reverse (1023400220344), we get a palindrome (5453620263545).

The spelling of 4430220043201 in words is "four trillion, four hundred thirty billion, two hundred twenty million, forty-three thousand, two hundred one".

Divisors: 1 961427 4607963 4430220043201