Base | Representation |
---|---|
bin | 100000001110111111010… |
… | …0100001111100101000111 |
3 | 120200112012200012121011121 |
4 | 1000131332210033211013 |
5 | 1040041110041244031 |
6 | 13231115521014411 |
7 | 635034226503505 |
oct | 100357644174507 |
9 | 16615180177147 |
10 | 4430234712391 |
11 | 1458940aa9984 |
12 | 5b6738784407 |
13 | 261a0031b027 |
14 | 1145d2ba7675 |
15 | 7a391de2011 |
hex | 4077e90f947 |
4430234712391 has 2 divisors, whose sum is σ = 4430234712392. Its totient is φ = 4430234712390.
The previous prime is 4430234712347. The next prime is 4430234712439. The reversal of 4430234712391 is 1932174320344.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4430234712391 - 213 = 4430234704199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4430234712341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215117356195 + 2215117356196.
It is an arithmetic number, because the mean of its divisors is an integer number (2215117356196).
Almost surely, 24430234712391 is an apocalyptic number.
4430234712391 is a deficient number, since it is larger than the sum of its proper divisors (1).
4430234712391 is an equidigital number, since it uses as much as digits as its factorization.
4430234712391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 435456, while the sum is 43.
The spelling of 4430234712391 in words is "four trillion, four hundred thirty billion, two hundred thirty-four million, seven hundred twelve thousand, three hundred ninety-one".
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