Base | Representation |
---|---|
bin | 110010010111011110100010… |
… | …0000011110111000000100110 |
3 | 2011002122101020222011120000101 |
4 | 1210232331010003313000212 |
5 | 431032111112213142014 |
6 | 4210125435313534314 |
7 | 162213645643613056 |
oct | 14456750403670046 |
9 | 2132571228146011 |
10 | 443031313412134 |
11 | 119188585689447 |
12 | 4183252a57439a |
13 | 1602889ab60135 |
14 | 7b58b89677566 |
15 | 36343db657474 |
hex | 192ef440f7026 |
443031313412134 has 16 divisors (see below), whose sum is σ = 688056428307456. Its totient is φ = 213722346875400.
The previous prime is 443031313412119. The next prime is 443031313412147. The reversal of 443031313412134 is 431214313130344.
It is a junction number, because it is equal to n+sod(n) for n = 443031313412093 and 443031313412102.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10794037402 + ... + 10794078445.
It is an arithmetic number, because the mean of its divisors is an integer number (43003526769216).
Almost surely, 2443031313412134 is an apocalyptic number.
443031313412134 is a deficient number, since it is larger than the sum of its proper divisors (245025114895322).
443031313412134 is a wasteful number, since it uses less digits than its factorization.
443031313412134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21588116211.
The product of its (nonzero) digits is 124416, while the sum is 37.
Adding to 443031313412134 its reverse (431214313130344), we get a palindrome (874245626542478).
The spelling of 443031313412134 in words is "four hundred forty-three trillion, thirty-one billion, three hundred thirteen million, four hundred twelve thousand, one hundred thirty-four".
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