Base | Representation |
---|---|
bin | 100000001111011001101… |
… | …1001001111010011010001 |
3 | 120200121111102221200210112 |
4 | 1000132303121033103101 |
5 | 1040044413440120423 |
6 | 13231343501411105 |
7 | 635065211134154 |
oct | 100366331172321 |
9 | 16617442850715 |
10 | 4431121020113 |
11 | 1459256329aa7 |
12 | 5b6945569a95 |
13 | 261b11b2c378 |
14 | 11467879bc9b |
15 | 7a3e4b16a78 |
hex | 407b364f4d1 |
4431121020113 has 2 divisors, whose sum is σ = 4431121020114. Its totient is φ = 4431121020112.
The previous prime is 4431121020091. The next prime is 4431121020173. The reversal of 4431121020113 is 3110201211344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3952688730769 + 478432289344 = 1988137^2 + 691688^2 .
It is a cyclic number.
It is not a de Polignac number, because 4431121020113 - 26 = 4431121020049 is a prime.
It is not a weakly prime, because it can be changed into another prime (4431121020173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215560510056 + 2215560510057.
It is an arithmetic number, because the mean of its divisors is an integer number (2215560510057).
Almost surely, 24431121020113 is an apocalyptic number.
It is an amenable number.
4431121020113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431121020113 is an equidigital number, since it uses as much as digits as its factorization.
4431121020113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 4431121020113 its reverse (3110201211344), we get a palindrome (7541322231457).
The spelling of 4431121020113 in words is "four trillion, four hundred thirty-one billion, one hundred twenty-one million, twenty thousand, one hundred thirteen".
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