Base | Representation |
---|---|
bin | 100000001111011010000… |
… | …1011111110110111011111 |
3 | 120200121112100222111202022 |
4 | 1000132310023332313133 |
5 | 1040044430341302033 |
6 | 13231345054450355 |
7 | 635065432165454 |
oct | 100366413766737 |
9 | 16617470874668 |
10 | 4431134322143 |
11 | 1459262895011 |
12 | 5b6949b039bb |
13 | 261b14808ba9 |
14 | 11467a46182b |
15 | 7a3e5d93098 |
hex | 407b42feddf |
4431134322143 has 2 divisors, whose sum is σ = 4431134322144. Its totient is φ = 4431134322142.
The previous prime is 4431134322137. The next prime is 4431134322169. The reversal of 4431134322143 is 3412234311344.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4431134322143 - 24 = 4431134322127 is a prime.
It is a super-2 number, since 2×44311343221432 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4431134321143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215567161071 + 2215567161072.
It is an arithmetic number, because the mean of its divisors is an integer number (2215567161072).
Almost surely, 24431134322143 is an apocalyptic number.
4431134322143 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431134322143 is an equidigital number, since it uses as much as digits as its factorization.
4431134322143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 82944, while the sum is 35.
Adding to 4431134322143 its reverse (3412234311344), we get a palindrome (7843368633487).
The spelling of 4431134322143 in words is "four trillion, four hundred thirty-one billion, one hundred thirty-four million, three hundred twenty-two thousand, one hundred forty-three".
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