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443120040119 is a prime number
BaseRepresentation
bin1100111001011000000…
…00110011100010110111
31120100202210112100220202
412130230000303202313
524230002212240434
6535322212151115
744004633123461
oct6345400634267
91510683470822
10443120040119
11160a2078a799
1271a6800849b
1332a2ac14393
1417638ca3131
15b7d7286a7e
hex672c0338b7

443120040119 has 2 divisors, whose sum is σ = 443120040120. Its totient is φ = 443120040118.

The previous prime is 443120040091. The next prime is 443120040127. The reversal of 443120040119 is 911040021344.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 443120040119 - 232 = 438825072823 is a prime.

It is a super-2 number, since 2×4431200401192 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 443120040091 and 443120040100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (443123040119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221560020059 + 221560020060.

It is an arithmetic number, because the mean of its divisors is an integer number (221560020060).

Almost surely, 2443120040119 is an apocalyptic number.

443120040119 is a deficient number, since it is larger than the sum of its proper divisors (1).

443120040119 is an equidigital number, since it uses as much as digits as its factorization.

443120040119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

The spelling of 443120040119 in words is "four hundred forty-three billion, one hundred twenty million, forty thousand, one hundred nineteen".