Base | Representation |
---|---|
bin | 101001010001001101… |
… | …011010000100010111 |
3 | 11020101012010001102021 |
4 | 221101031122010113 |
5 | 1211222402021403 |
6 | 32205014554011 |
7 | 3126044664445 |
oct | 512115320427 |
9 | 136335101367 |
10 | 44312142103 |
11 | 1787a05a249 |
12 | 8708068907 |
13 | 4242563638 |
14 | 2205175b95 |
15 | 12453688bd |
hex | a5135a117 |
44312142103 has 2 divisors, whose sum is σ = 44312142104. Its totient is φ = 44312142102.
The previous prime is 44312142097. The next prime is 44312142169. The reversal of 44312142103 is 30124121344.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 44312142103 - 29 = 44312141591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44312142503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22156071051 + 22156071052.
It is an arithmetic number, because the mean of its divisors is an integer number (22156071052).
Almost surely, 244312142103 is an apocalyptic number.
44312142103 is a deficient number, since it is larger than the sum of its proper divisors (1).
44312142103 is an equidigital number, since it uses as much as digits as its factorization.
44312142103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 44312142103 its reverse (30124121344), we get a palindrome (74436263447).
The spelling of 44312142103 in words is "forty-four billion, three hundred twelve million, one hundred forty-two thousand, one hundred three".
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