Base | Representation |
---|---|
bin | 10100001001101001110011… |
… | …00110100110010001000011 |
3 | 12210220012101111122111011010 |
4 | 22010310321212212101003 |
5 | 21302002232331343410 |
6 | 234124415023452003 |
7 | 12222306144300162 |
oct | 1204647146462103 |
9 | 183805344574133 |
10 | 44312144012355 |
11 | 1313474709718a |
12 | 4b77ba7457003 |
13 | 1b9580413a00b |
14 | ad2a0d7453d9 |
15 | 51c9d95a1c20 |
hex | 284d399a6443 |
44312144012355 has 32 divisors (see below), whose sum is σ = 72282731155200. Its totient is φ = 23174061178752.
The previous prime is 44312144012327. The next prime is 44312144012359. The reversal of 44312144012355 is 55321044121344.
It is not a de Polignac number, because 44312144012355 - 26 = 44312144012291 is a prime.
It is a super-2 number, since 2×443121440123552 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (44312144012359) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 62709385 + ... + 63412074.
It is an arithmetic number, because the mean of its divisors is an integer number (2258835348600).
Almost surely, 244312144012355 is an apocalyptic number.
44312144012355 is a deficient number, since it is larger than the sum of its proper divisors (27970587142845).
44312144012355 is a wasteful number, since it uses less digits than its factorization.
44312144012355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126121923.
The product of its (nonzero) digits is 230400, while the sum is 39.
Adding to 44312144012355 its reverse (55321044121344), we get a palindrome (99633188133699).
The spelling of 44312144012355 in words is "forty-four trillion, three hundred twelve billion, one hundred forty-four million, twelve thousand, three hundred fifty-five".
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