Base | Representation |
---|---|
bin | 100000001111011100101… |
… | …1110101110100011000001 |
3 | 120200121202120002000102002 |
4 | 1000132321132232203001 |
5 | 1040100121104401423 |
6 | 13231401550033345 |
7 | 635100561032504 |
oct | 100367136564301 |
9 | 16617676060362 |
10 | 4431223122113 |
11 | 14592a8a26817 |
12 | 5b69737a8855 |
13 | 261b2a02a858 |
14 | 11468817913b |
15 | 7a3eda84228 |
hex | 407b97ae8c1 |
4431223122113 has 4 divisors (see below), whose sum is σ = 4497360780720. Its totient is φ = 4365085463508.
The previous prime is 4431223122107. The next prime is 4431223122133. The reversal of 4431223122113 is 3112213221344.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4431223122113 - 24 = 4431223122097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4431223122133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33068829203 + ... + 33068829336.
It is an arithmetic number, because the mean of its divisors is an integer number (1124340195180).
Almost surely, 24431223122113 is an apocalyptic number.
It is an amenable number.
4431223122113 is a deficient number, since it is larger than the sum of its proper divisors (66137658607).
4431223122113 is an equidigital number, since it uses as much as digits as its factorization.
4431223122113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66137658606.
The product of its digits is 6912, while the sum is 29.
Adding to 4431223122113 its reverse (3112213221344), we get a palindrome (7543436343457).
The spelling of 4431223122113 in words is "four trillion, four hundred thirty-one billion, two hundred twenty-three million, one hundred twenty-two thousand, one hundred thirteen".
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