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4431223122113 = 6766137658539
BaseRepresentation
bin100000001111011100101…
…1110101110100011000001
3120200121202120002000102002
41000132321132232203001
51040100121104401423
613231401550033345
7635100561032504
oct100367136564301
916617676060362
104431223122113
1114592a8a26817
125b69737a8855
13261b2a02a858
1411468817913b
157a3eda84228
hex407b97ae8c1

4431223122113 has 4 divisors (see below), whose sum is σ = 4497360780720. Its totient is φ = 4365085463508.

The previous prime is 4431223122107. The next prime is 4431223122133. The reversal of 4431223122113 is 3112213221344.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4431223122113 - 24 = 4431223122097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4431223122133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33068829203 + ... + 33068829336.

It is an arithmetic number, because the mean of its divisors is an integer number (1124340195180).

Almost surely, 24431223122113 is an apocalyptic number.

It is an amenable number.

4431223122113 is a deficient number, since it is larger than the sum of its proper divisors (66137658607).

4431223122113 is an equidigital number, since it uses as much as digits as its factorization.

4431223122113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66137658606.

The product of its digits is 6912, while the sum is 29.

Adding to 4431223122113 its reverse (3112213221344), we get a palindrome (7543436343457).

The spelling of 4431223122113 in words is "four trillion, four hundred thirty-one billion, two hundred twenty-three million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 67 66137658539 4431223122113