Base | Representation |
---|---|
bin | 100000001111011111000… |
… | …0100011101011001011001 |
3 | 120200121221220222000200012 |
4 | 1000132332010131121121 |
5 | 1040100300312402301 |
6 | 13231413340251305 |
7 | 635102514362531 |
oct | 100367604353131 |
9 | 16617856860605 |
10 | 4431300122201 |
11 | 1459338439057 |
12 | 5b6995540b35 |
13 | 261b3cc7a634 |
14 | 1146944a04c1 |
15 | 7a4056e3ebb |
hex | 407be11d659 |
4431300122201 has 2 divisors, whose sum is σ = 4431300122202. Its totient is φ = 4431300122200.
The previous prime is 4431300122189. The next prime is 4431300122219. The reversal of 4431300122201 is 1022210031344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2379676464400 + 2051623657801 = 1542620^2 + 1432349^2 .
It is a cyclic number.
It is not a de Polignac number, because 4431300122201 - 222 = 4431295927897 is a prime.
It is not a weakly prime, because it can be changed into another prime (4431300122231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215650061100 + 2215650061101.
It is an arithmetic number, because the mean of its divisors is an integer number (2215650061101).
Almost surely, 24431300122201 is an apocalyptic number.
It is an amenable number.
4431300122201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431300122201 is an equidigital number, since it uses as much as digits as its factorization.
4431300122201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4431300122201 its reverse (1022210031344), we get a palindrome (5453510153545).
The spelling of 4431300122201 in words is "four trillion, four hundred thirty-one billion, three hundred million, one hundred twenty-two thousand, two hundred one".
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