Base | Representation |
---|---|
bin | 101001010001010000… |
… | …101111000010100001 |
3 | 11020101020202101000210 |
4 | 221101100233002201 |
5 | 1211223112430213 |
6 | 32205045404333 |
7 | 3126055256622 |
oct | 512120570241 |
9 | 136336671023 |
10 | 44313014433 |
11 | 1787a5a5686 |
12 | 87084096a9 |
13 | 42427aa6cc |
14 | 2205321a49 |
15 | 124548c0c3 |
hex | a5142f0a1 |
44313014433 has 4 divisors (see below), whose sum is σ = 59084019248. Its totient is φ = 29542009620.
The previous prime is 44313014381. The next prime is 44313014479. The reversal of 44313014433 is 33441031344.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 44313014433 - 221 = 44310917281 is a prime.
It is a super-2 number, since 2×443130144332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 44313014433.
It is not an unprimeable number, because it can be changed into a prime (44313014483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7385502403 + ... + 7385502408.
It is an arithmetic number, because the mean of its divisors is an integer number (14771004812).
Almost surely, 244313014433 is an apocalyptic number.
It is an amenable number.
44313014433 is a deficient number, since it is larger than the sum of its proper divisors (14771004815).
44313014433 is a wasteful number, since it uses less digits than its factorization.
44313014433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14771004814.
The product of its (nonzero) digits is 20736, while the sum is 30.
Adding to 44313014433 its reverse (33441031344), we get a palindrome (77754045777).
The spelling of 44313014433 in words is "forty-four billion, three hundred thirteen million, fourteen thousand, four hundred thirty-three".
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