4431304012411 has 4 divisors (see below), whose sum is σ = 4664530539400. Its totient is φ = 4198077485424.

The previous prime is 4431304012393. The next prime is 4431304012477. The reversal of 4431304012411 is 1142104031344.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4431304012411 - 2⁵ = 4431304012379 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4431304012411.

It is not an unprimeable number, because it can be changed into a prime (4431304019411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116613263466 + ... + 116613263503.

It is an arithmetic number, because the mean of its divisors is an integer number (1166132634850).

Almost surely, 2^{4431304012411} is an apocalyptic number.

4431304012411 is a deficient number, since it is larger than the sum of its proper divisors (233226526989).

4431304012411 is a wasteful number, since it uses less digits than its factorization.

4431304012411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 233226526988.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 4431304012411 its reverse (1142104031344), we get a palindrome (5573408043755).

The spelling of 4431304012411 in words is "four trillion, four hundred thirty-one billion, three hundred four million, twelve thousand, four hundred eleven".