443141224040101 has 4 divisors (see below), whose sum is σ = 443857122625600. Its totient is φ = 442425325454604.

The previous prime is 443141224040093. The next prime is 443141224040161. The reversal of 443141224040101 is 101040422141344.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 443141224040101 - 2³ = 443141224040093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (443141224040161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357949291821 + ... + 357949293058.

It is an arithmetic number, because the mean of its divisors is an integer number (110964280656400).

Almost surely, 2^{443141224040101} is an apocalyptic number.

It is an amenable number.

443141224040101 is a deficient number, since it is larger than the sum of its proper divisors (715898585499).

443141224040101 is an equidigital number, since it uses as much as digits as its factorization.

443141224040101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 715898585498.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 443141224040101 its reverse (101040422141344), we get a palindrome (544181646181445).

The spelling of 443141224040101 in words is "four hundred forty-three trillion, one hundred forty-one billion, two hundred twenty-four million, forty thousand, one hundred one".