Base | Representation |
---|---|
bin | 100000001111100101011… |
… | …0001000110001010101001 |
3 | 120200122111202210222001011 |
4 | 1000133022301012022221 |
5 | 1040101214331300441 |
6 | 13231450430223521 |
7 | 635111012160301 |
oct | 100371261061251 |
9 | 16618452728034 |
10 | 4431513150121 |
11 | 145943770a092 |
12 | 5b6a34954ba1 |
13 | 261b75146765 |
14 | 1146b48b4601 |
15 | 7a419273581 |
hex | 407cac462a9 |
4431513150121 has 2 divisors, whose sum is σ = 4431513150122. Its totient is φ = 4431513150120.
The previous prime is 4431513150109. The next prime is 4431513150137. The reversal of 4431513150121 is 1210513151344.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3419096846400 + 1012416303721 = 1849080^2 + 1006189^2 .
It is a cyclic number.
It is not a de Polignac number, because 4431513150121 - 217 = 4431513019049 is a prime.
It is not a weakly prime, because it can be changed into another prime (4431513150191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215756575060 + 2215756575061.
It is an arithmetic number, because the mean of its divisors is an integer number (2215756575061).
Almost surely, 24431513150121 is an apocalyptic number.
It is an amenable number.
4431513150121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431513150121 is an equidigital number, since it uses as much as digits as its factorization.
4431513150121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
The spelling of 4431513150121 in words is "four trillion, four hundred thirty-one billion, five hundred thirteen million, one hundred fifty thousand, one hundred twenty-one".
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