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443200222141 is a prime number
BaseRepresentation
bin1100111001100001100…
…10101011001110111101
31120100222101102000222021
412130300302223032331
524230133224102031
6535334154520141
744006625505345
oct6346062531675
91510871360867
10443200222141
11160a61a75726
1271a8aa36051
1332a41709571
14176457b5d25
15b7de324511
hex6730cab3bd

443200222141 has 2 divisors, whose sum is σ = 443200222142. Its totient is φ = 443200222140.

The previous prime is 443200222109. The next prime is 443200222169. The reversal of 443200222141 is 141222002344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 414111555225 + 29088666916 = 643515^2 + 170554^2 .

It is a cyclic number.

It is not a de Polignac number, because 443200222141 - 25 = 443200222109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (443200202141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221600111070 + 221600111071.

It is an arithmetic number, because the mean of its divisors is an integer number (221600111071).

Almost surely, 2443200222141 is an apocalyptic number.

It is an amenable number.

443200222141 is a deficient number, since it is larger than the sum of its proper divisors (1).

443200222141 is an equidigital number, since it uses as much as digits as its factorization.

443200222141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 443200222141 its reverse (141222002344), we get a palindrome (584422224485).

The spelling of 443200222141 in words is "four hundred forty-three billion, two hundred million, two hundred twenty-two thousand, one hundred forty-one".