Base | Representation |
---|---|
bin | 110010011000101110000001… |
… | …0111110010001100110110011 |
3 | 2011010020200212210221212110112 |
4 | 1210301130002332101212303 |
5 | 431042410214122333021 |
6 | 4210340110335051535 |
7 | 162232201135654004 |
oct | 14461340276214663 |
9 | 2133220783855415 |
10 | 443202020121011 |
11 | 119243a15118438 |
12 | 4185b62b970bab |
13 | 1603ba04335148 |
14 | 7b631411131ab |
15 | 3638a7d04cd5b |
hex | 1931702f919b3 |
443202020121011 has 8 divisors (see below), whose sum is σ = 444873465772848. Its totient is φ = 441531242656000.
The previous prime is 443202020120953. The next prime is 443202020121013. The reversal of 443202020121011 is 110121020202344.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 443202020121011 - 210 = 443202020119987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (443202020121013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 165717605 + ... + 168370806.
It is an arithmetic number, because the mean of its divisors is an integer number (55609183221606).
Almost surely, 2443202020121011 is an apocalyptic number.
443202020121011 is a deficient number, since it is larger than the sum of its proper divisors (1671445651837).
443202020121011 is a wasteful number, since it uses less digits than its factorization.
443202020121011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 334093413.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 443202020121011 its reverse (110121020202344), we get a palindrome (553323040323355).
The spelling of 443202020121011 in words is "four hundred forty-three trillion, two hundred two billion, twenty million, one hundred twenty-one thousand, eleven".
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