Base | Representation |
---|---|
bin | 101001010001111110… |
… | …011101010011010111 |
3 | 11020102002022022200202 |
4 | 221101332131103113 |
5 | 1211234200003112 |
6 | 32210154331115 |
7 | 3126262200302 |
oct | 512176352327 |
9 | 136362268622 |
10 | 44325000407 |
11 | 17886341946 |
12 | 8710429a9b |
13 | 42451161bc |
14 | 2206b61b39 |
15 | 12465586c2 |
hex | a51f9d4d7 |
44325000407 has 2 divisors, whose sum is σ = 44325000408. Its totient is φ = 44325000406.
The previous prime is 44325000403. The next prime is 44325000427. The reversal of 44325000407 is 70400052344.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 44325000407 - 22 = 44325000403 is a prime.
It is a super-2 number, since 2×443250004072 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 44325000407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44325000403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22162500203 + 22162500204.
It is an arithmetic number, because the mean of its divisors is an integer number (22162500204).
Almost surely, 244325000407 is an apocalyptic number.
44325000407 is a deficient number, since it is larger than the sum of its proper divisors (1).
44325000407 is an equidigital number, since it uses as much as digits as its factorization.
44325000407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 29.
The spelling of 44325000407 in words is "forty-four billion, three hundred twenty-five million, four hundred seven", and thus it is an aban number.
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