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44331130001 is a prime number
BaseRepresentation
bin101001010010010101…
…110101110010010001
311020102111211201220202
4221102111311302101
51211242232130001
632210533544545
73126365246654
oct512225656221
9136374751822
1044331130001
1117889849124
1287124a5155
134246481192
1422078b989b
151246d6996b
hexa52575c91

44331130001 has 2 divisors, whose sum is σ = 44331130002. Its totient is φ = 44331130000.

The previous prime is 44331129991. The next prime is 44331130009. The reversal of 44331130001 is 10003113344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44259744400 + 71385601 = 210380^2 + 8449^2 .

It is a cyclic number.

It is not a de Polignac number, because 44331130001 - 230 = 43257388177 is a prime.

It is not a weakly prime, because it can be changed into another prime (44331130009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22165565000 + 22165565001.

It is an arithmetic number, because the mean of its divisors is an integer number (22165565001).

Almost surely, 244331130001 is an apocalyptic number.

It is an amenable number.

44331130001 is a deficient number, since it is larger than the sum of its proper divisors (1).

44331130001 is an equidigital number, since it uses as much as digits as its factorization.

44331130001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 44331130001 its reverse (10003113344), we get a palindrome (54334243345).

The spelling of 44331130001 in words is "forty-four billion, three hundred thirty-one million, one hundred thirty thousand, one".