Base | Representation |
---|---|
bin | 101001010010010101… |
… | …110101110010010001 |
3 | 11020102111211201220202 |
4 | 221102111311302101 |
5 | 1211242232130001 |
6 | 32210533544545 |
7 | 3126365246654 |
oct | 512225656221 |
9 | 136374751822 |
10 | 44331130001 |
11 | 17889849124 |
12 | 87124a5155 |
13 | 4246481192 |
14 | 22078b989b |
15 | 1246d6996b |
hex | a52575c91 |
44331130001 has 2 divisors, whose sum is σ = 44331130002. Its totient is φ = 44331130000.
The previous prime is 44331129991. The next prime is 44331130009. The reversal of 44331130001 is 10003113344.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44259744400 + 71385601 = 210380^2 + 8449^2 .
It is a cyclic number.
It is not a de Polignac number, because 44331130001 - 230 = 43257388177 is a prime.
It is not a weakly prime, because it can be changed into another prime (44331130009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22165565000 + 22165565001.
It is an arithmetic number, because the mean of its divisors is an integer number (22165565001).
Almost surely, 244331130001 is an apocalyptic number.
It is an amenable number.
44331130001 is a deficient number, since it is larger than the sum of its proper divisors (1).
44331130001 is an equidigital number, since it uses as much as digits as its factorization.
44331130001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 44331130001 its reverse (10003113344), we get a palindrome (54334243345).
The spelling of 44331130001 in words is "forty-four billion, three hundred thirty-one million, one hundred thirty thousand, one".
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