Base | Representation |
---|---|
bin | 10100001010010001000010… |
… | …11110011000010000101100 |
3 | 12210222012202220121211221022 |
4 | 22011020201132120100230 |
5 | 21302323410243304012 |
6 | 234142221455353312 |
7 | 12223653241501412 |
oct | 1205104136302054 |
9 | 183865686554838 |
10 | 44333214041132 |
11 | 1314267961a705 |
12 | 4b800a7822838 |
13 | 1b977b1400773 |
14 | ad3a4bba72b2 |
15 | 51d31e233472 |
hex | 28522179842c |
44333214041132 has 6 divisors (see below), whose sum is σ = 77583124571988. Its totient is φ = 22166607020564.
The previous prime is 44333214041113. The next prime is 44333214041159. The reversal of 44333214041132 is 23114041233344.
It is a junction number, because it is equal to n+sod(n) for n = 44333214041092 and 44333214041101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5541651755138 + ... + 5541651755145.
It is an arithmetic number, because the mean of its divisors is an integer number (12930520761998).
Almost surely, 244333214041132 is an apocalyptic number.
It is an amenable number.
44333214041132 is a deficient number, since it is larger than the sum of its proper divisors (33249910530856).
44333214041132 is a wasteful number, since it uses less digits than its factorization.
44333214041132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11083303510287 (or 11083303510285 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 44333214041132 its reverse (23114041233344), we get a palindrome (67447255274476).
The spelling of 44333214041132 in words is "forty-four trillion, three hundred thirty-three billion, two hundred fourteen million, forty-one thousand, one hundred thirty-two".
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