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44333214041132 = 2211083303510283
BaseRepresentation
bin10100001010010001000010…
…11110011000010000101100
312210222012202220121211221022
422011020201132120100230
521302323410243304012
6234142221455353312
712223653241501412
oct1205104136302054
9183865686554838
1044333214041132
111314267961a705
124b800a7822838
131b977b1400773
14ad3a4bba72b2
1551d31e233472
hex28522179842c

44333214041132 has 6 divisors (see below), whose sum is σ = 77583124571988. Its totient is φ = 22166607020564.

The previous prime is 44333214041113. The next prime is 44333214041159. The reversal of 44333214041132 is 23114041233344.

It is a junction number, because it is equal to n+sod(n) for n = 44333214041092 and 44333214041101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5541651755138 + ... + 5541651755145.

It is an arithmetic number, because the mean of its divisors is an integer number (12930520761998).

Almost surely, 244333214041132 is an apocalyptic number.

It is an amenable number.

44333214041132 is a deficient number, since it is larger than the sum of its proper divisors (33249910530856).

44333214041132 is a wasteful number, since it uses less digits than its factorization.

44333214041132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11083303510287 (or 11083303510285 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 44333214041132 its reverse (23114041233344), we get a palindrome (67447255274476).

The spelling of 44333214041132 in words is "forty-four trillion, three hundred thirty-three billion, two hundred fourteen million, forty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 11083303510283 22166607020566 44333214041132