Base | Representation |
---|---|
bin | 101001010010100000… |
… | …111100110000010101 |
3 | 11020102201022200121111 |
4 | 221102200330300111 |
5 | 1211244003322013 |
6 | 32211120215021 |
7 | 3126432066103 |
oct | 512240746025 |
9 | 136381280544 |
10 | 44334042133 |
11 | 17890458047 |
12 | 871346a471 |
13 | 4246c60834 |
14 | 2208036c73 |
15 | 124724273d |
hex | a5283cc15 |
44334042133 has 8 divisors (see below), whose sum is σ = 45176237568. Its totient is φ = 43492058064.
The previous prime is 44334042101. The next prime is 44334042163. The reversal of 44334042133 is 33124043344.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 44334042133 - 25 = 44334042101 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 44334042095 and 44334042104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44334042163) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 408516 + ... + 505522.
It is an arithmetic number, because the mean of its divisors is an integer number (5647029696).
Almost surely, 244334042133 is an apocalyptic number.
It is an amenable number.
44334042133 is a deficient number, since it is larger than the sum of its proper divisors (842195435).
44334042133 is an equidigital number, since it uses as much as digits as its factorization.
44334042133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105683.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 44334042133 its reverse (33124043344), we get a palindrome (77458085477).
The spelling of 44334042133 in words is "forty-four billion, three hundred thirty-four million, forty-two thousand, one hundred thirty-three".
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