Base | Representation |
---|---|
bin | 100000010000011110010… |
… | …1011101110100101001101 |
3 | 120200211102222001202010021 |
4 | 1000200330223232211031 |
5 | 1040114123113023141 |
6 | 13232404221542141 |
7 | 635206250105251 |
oct | 100407453564515 |
9 | 16624388052107 |
10 | 4433424345421 |
11 | 145a228511435 |
12 | 5b7288a14951 |
13 | 2620bb099c56 |
14 | 114816654261 |
15 | 7a4cbe436d1 |
hex | 4083caee94d |
4433424345421 has 2 divisors, whose sum is σ = 4433424345422. Its totient is φ = 4433424345420.
The previous prime is 4433424345289. The next prime is 4433424345517. The reversal of 4433424345421 is 1245434243344.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4433403969225 + 20376196 = 2105565^2 + 4514^2 .
It is a cyclic number.
It is not a de Polignac number, because 4433424345421 - 211 = 4433424343373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4433424342421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2216712172710 + 2216712172711.
It is an arithmetic number, because the mean of its divisors is an integer number (2216712172711).
Almost surely, 24433424345421 is an apocalyptic number.
It is an amenable number.
4433424345421 is a deficient number, since it is larger than the sum of its proper divisors (1).
4433424345421 is an equidigital number, since it uses as much as digits as its factorization.
4433424345421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2211840, while the sum is 43.
Adding to 4433424345421 its reverse (1245434243344), we get a palindrome (5678858588765).
The spelling of 4433424345421 in words is "four trillion, four hundred thirty-three billion, four hundred twenty-four million, three hundred forty-five thousand, four hundred twenty-one".
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