Base | Representation |
---|---|
bin | 100000010000011110010… |
… | …1011101110100110101001 |
3 | 120200211102222001202020200 |
4 | 1000200330223232212221 |
5 | 1040114123113024023 |
6 | 13232404221542413 |
7 | 635206250105442 |
oct | 100407453564651 |
9 | 16624388052220 |
10 | 4433424345513 |
11 | 145a228511509 |
12 | 5b7288a14a09 |
13 | 2620bb099cc7 |
14 | 1148166542c9 |
15 | 7a4cbe43743 |
hex | 4083caee9a9 |
4433424345513 has 12 divisors (see below), whose sum is σ = 6405263694960. Its totient is φ = 2954956909176.
The previous prime is 4433424345421. The next prime is 4433424345517. The reversal of 4433424345513 is 3155434243344.
4433424345513 is a `hidden beast` number, since 4 + 43 + 3 + 4 + 24 + 34 + 551 + 3 = 666.
It is not a de Polignac number, because 4433424345513 - 212 = 4433424341417 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4433424345517) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 54900843 + ... + 54981536.
It is an arithmetic number, because the mean of its divisors is an integer number (533771974580).
Almost surely, 24433424345513 is an apocalyptic number.
It is an amenable number.
4433424345513 is a deficient number, since it is larger than the sum of its proper divisors (1971839349447).
4433424345513 is a wasteful number, since it uses less digits than its factorization.
4433424345513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109886868 (or 109886865 counting only the distinct ones).
The product of its digits is 4147200, while the sum is 45.
Adding to 4433424345513 its reverse (3155434243344), we get a palindrome (7588858588857).
The spelling of 4433424345513 in words is "four trillion, four hundred thirty-three billion, four hundred twenty-four million, three hundred forty-five thousand, five hundred thirteen".
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