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4434314212403 = 38891114019033
BaseRepresentation
bin100000010000111000110…
…1110010011010000110011
3120200220201222111200010122
41000201301232103100303
51040122433414244103
613233032410520455
7635240303621525
oct100416156232063
916626658450118
104434314212403
11145a644852699
125b7496a3612b
1326220055636a
1411489c8d3a15
157a53011cb38
hex40871b93433

4434314212403 has 4 divisors (see below), whose sum is σ = 4434428270328. Its totient is φ = 4434200154480.

The previous prime is 4434314212397. The next prime is 4434314212409. The reversal of 4434314212403 is 3042124134344.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (4434314212397) and next prime (4434314212409).

It is a cyclic number.

It is not a de Polignac number, because 4434314212403 - 212 = 4434314208307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4434314212409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56970626 + ... + 57048407.

It is an arithmetic number, because the mean of its divisors is an integer number (1108607067582).

Almost surely, 24434314212403 is an apocalyptic number.

4434314212403 is a deficient number, since it is larger than the sum of its proper divisors (114057925).

4434314212403 is a wasteful number, since it uses less digits than its factorization.

4434314212403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114057924.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 4434314212403 its reverse (3042124134344), we get a palindrome (7476438346747).

The spelling of 4434314212403 in words is "four trillion, four hundred thirty-four billion, three hundred fourteen million, two hundred twelve thousand, four hundred three".

Divisors: 1 38891 114019033 4434314212403