Base | Representation |
---|---|
bin | 100000010000111000110… |
… | …1110010011010000110011 |
3 | 120200220201222111200010122 |
4 | 1000201301232103100303 |
5 | 1040122433414244103 |
6 | 13233032410520455 |
7 | 635240303621525 |
oct | 100416156232063 |
9 | 16626658450118 |
10 | 4434314212403 |
11 | 145a644852699 |
12 | 5b7496a3612b |
13 | 26220055636a |
14 | 11489c8d3a15 |
15 | 7a53011cb38 |
hex | 40871b93433 |
4434314212403 has 4 divisors (see below), whose sum is σ = 4434428270328. Its totient is φ = 4434200154480.
The previous prime is 4434314212397. The next prime is 4434314212409. The reversal of 4434314212403 is 3042124134344.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (4434314212397) and next prime (4434314212409).
It is a cyclic number.
It is not a de Polignac number, because 4434314212403 - 212 = 4434314208307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4434314212409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56970626 + ... + 57048407.
It is an arithmetic number, because the mean of its divisors is an integer number (1108607067582).
Almost surely, 24434314212403 is an apocalyptic number.
4434314212403 is a deficient number, since it is larger than the sum of its proper divisors (114057925).
4434314212403 is a wasteful number, since it uses less digits than its factorization.
4434314212403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114057924.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 4434314212403 its reverse (3042124134344), we get a palindrome (7476438346747).
The spelling of 4434314212403 in words is "four trillion, four hundred thirty-four billion, three hundred fourteen million, two hundred twelve thousand, four hundred three".
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