Base | Representation |
---|---|
bin | 100000010000111001000… |
… | …0101001110010000100111 |
3 | 120200220202101210221200112 |
4 | 1000201302011032100213 |
5 | 1040122441434034343 |
6 | 13233033143403235 |
7 | 635240405656124 |
oct | 100416205162047 |
9 | 16626671727615 |
10 | 4434320221223 |
11 | 145a648187162 |
12 | 5b7498a5351b |
13 | 26220187b389 |
14 | 11489d61974b |
15 | 7a530908218 |
hex | 4087214e427 |
4434320221223 has 2 divisors, whose sum is σ = 4434320221224. Its totient is φ = 4434320221222.
The previous prime is 4434320221159. The next prime is 4434320221229. The reversal of 4434320221223 is 3221220234344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4434320221223 - 26 = 4434320221159 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4434320221223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4434320221229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2217160110611 + 2217160110612.
It is an arithmetic number, because the mean of its divisors is an integer number (2217160110612).
Almost surely, 24434320221223 is an apocalyptic number.
4434320221223 is a deficient number, since it is larger than the sum of its proper divisors (1).
4434320221223 is an equidigital number, since it uses as much as digits as its factorization.
4434320221223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 4434320221223 its reverse (3221220234344), we get a palindrome (7655540455567).
The spelling of 4434320221223 in words is "four trillion, four hundred thirty-four billion, three hundred twenty million, two hundred twenty-one thousand, two hundred twenty-three".
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