Base | Representation |
---|---|
bin | 100000010000111001000… |
… | …0101001110010010001011 |
3 | 120200220202101210221211020 |
4 | 1000201302011032102023 |
5 | 1040122441434040243 |
6 | 13233033143403523 |
7 | 635240405656326 |
oct | 100416205162213 |
9 | 16626671727736 |
10 | 4434320221323 |
11 | 145a648187243 |
12 | 5b7498a535a3 |
13 | 26220187b435 |
14 | 11489d6197bd |
15 | 7a530908283 |
hex | 4087214e48b |
4434320221323 has 4 divisors (see below), whose sum is σ = 5912426961768. Its totient is φ = 2956213480880.
The previous prime is 4434320221319. The next prime is 4434320221339. The reversal of 4434320221323 is 3231220234344.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4434320221323 - 22 = 4434320221319 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4434320221223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 739053370218 + ... + 739053370223.
It is an arithmetic number, because the mean of its divisors is an integer number (1478106740442).
Almost surely, 24434320221323 is an apocalyptic number.
4434320221323 is a deficient number, since it is larger than the sum of its proper divisors (1478106740445).
4434320221323 is a wasteful number, since it uses less digits than its factorization.
4434320221323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1478106740444.
The product of its (nonzero) digits is 82944, while the sum is 33.
Adding to 4434320221323 its reverse (3231220234344), we get a palindrome (7665540455667).
The spelling of 4434320221323 in words is "four trillion, four hundred thirty-four billion, three hundred twenty million, two hundred twenty-one thousand, three hundred twenty-three".
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