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44344064533133 is a prime number
BaseRepresentation
bin10100001010100101010000…
…01101101110001010001101
312211000020210002201221202102
422011102220031232022031
521303013121010030013
6234151214303204445
712224516154244031
oct1205225015561215
9184006702657672
1044344064533133
1113147237421972
124b822155a6725
131b9882036c131
14ad439ac7a1c1
1551d756addd58
hex2854a836e28d

44344064533133 has 2 divisors, whose sum is σ = 44344064533134. Its totient is φ = 44344064533132.

The previous prime is 44344064533121. The next prime is 44344064533159. The reversal of 44344064533133 is 33133546044344.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43793979760804 + 550084772329 = 6617702^2 + 741677^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44344064533133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44344064533633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22172032266566 + 22172032266567.

It is an arithmetic number, because the mean of its divisors is an integer number (22172032266567).

Almost surely, 244344064533133 is an apocalyptic number.

It is an amenable number.

44344064533133 is a deficient number, since it is larger than the sum of its proper divisors (1).

44344064533133 is an equidigital number, since it uses as much as digits as its factorization.

44344064533133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7464960, while the sum is 47.

The spelling of 44344064533133 in words is "forty-four trillion, three hundred forty-four billion, sixty-four million, five hundred thirty-three thousand, one hundred thirty-three".